Question

$$\int e^{ax}  \cosh bx \ dx $$

Accepted Answer

$$\begin{cases} \ \displaystyle{\frac{e^{ax}}{a^2-b^2} }[ -b \cosh bx + a \sinh bx ]  & a\ne b \ \displaystyle{\frac{e^{2ax}}{4a} - \frac{x}{2}} & a=b\end{cases}$$

Front	\[\int e^{ax} \cosh bx \ dx \]
Back	\[\begin{cases} \\ \displaystyle{\frac{e^{ax}}{a^2-b^2} }[ -b \cosh bx + a \sinh bx ] & a\ne b \\ \displaystyle{\frac{e^{2ax}}{4a} - \frac{x}{2}} & a=b\end{cases}\]

Bx Cosh Int E^{Ax Dx Begin{Cases Displaystyle{\Frac{E^{Ax}}{A^2 B^2 B