Int Sin^2 Ax Cos^2 Bx Dx Frac{X}{4} \Frac{\Sin 2ax}{8a} \Frac{\Sin[2(a B)x]}{16(a B)}+\Frac{\Sin

Front	\[\int \sin^2 ax \cos^2 bx dx \]
Back	\[ \frac{x}{4}-\frac{\sin 2ax}{8a}-\frac{\sin[2(a-b)x]}{16(a-b)}+\frac{\sin 2bx}{8b}-\frac{\sin[2(a+b)x]}{16(a+b)}\]

Tags: trigonometric

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